printf("%s", name);[Help with C] Is it possible to let the user define the scope of an array and the values of its elements?
I am just learning arrays and I am experimenting. This one simply won’t work. I am trying to have the user define (1) how many elements an int array can hold and (2) what the value of each elements is. The program now outputs random integers. Maybe this isn’t even possible, but I’m a complete beginner just playing around for the fun of it. XD
#include <stdio.h>
int main(void) {
int scope,elementnr,i,elementvalue,j;
scope = elementnr = i = elementvalue = j = 0;
int array[j];
printf("How many elements should your ARRAY hold: ");
scanf("%d", &scope);
getchar();
for (i = 0; i < scope; ++elementnr, ++i) {
printf("Enter the value of element number %d: ", elementnr + 1);
scanf("%d", &elementvalue);
getchar;
j = elementvalue;
}
printf("You have created an ARRAY that holds %d elements and you have assigned the following values:\n", scope);
for (i = 0; i < scope; ++i) printf("%d\n",array[j]);
}
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