GNU Octave 11 Open-Source Scientific Programming Language Officially Released

https://fed.brid.gy/r/https://9to5linux.com/gnu-octave-11-open-source-scientific-programming-language-officially-released

#GNU #Octave 11 Open-Source Scientific #Programming Language Officially Released, Here's What's New https://9to5linux.com/gnu-octave-11-open-source-scientific-programming-language-officially-released

#OpenSource #Linux #FReeSoftware

Yesterday, I dug up some old computational #physics code and something wonderful happend: it worked! Out of the box. Wicked!

I'd written some #matlab code back in ~2002 to solve the diffusion equation. Since I don't have Matlab anymore, I installed #octave and tried to run the code. Give it a go, see what happens. YOLO, and all that. And it ran without change! 😱 Even the plotting worked. I take my hat off to the Octave devs for ensuring such amazing compatibility. Thank you 😃

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https://

https://tfd.sourceforge.net/

#Octave #Analysis #Spectrogram

In der letzten Übung in den #GrundlagenDerElektrotechnik ging es um die #Maschenstromanalyse als Netzwerkberechnungsverfahren.

Ich das zugehörige #Gleichungssystem an der Tafel aufgestellt, wir haben dieses in #Octave gelöst und eine Probe im Netzwerksimulator #LTspice gemacht.

https://www.twitch.tv/mathiasmagdowski/v/2644361021

Updated at haikuports: Octave 10.3.0 (while cleaning up dependencies on lapack, this was one that was part of that).

http://www.octave.org/

#HaikuOS #haikuports #Octave #opensource

Yeah, I'm late, but AoC itself is scaled down this year due to burnout so gimme a break.

Here's #AdventOfCode Part 1 in two lines of #Matlab (actually I'm using #Octave). Map lines to numbers (L is negative), compute the cumulative sum with 50 as the starting value, mod by 100, and count the zeroes.

```
cells = importdata('input1.txt');
length(find(mod(cumsum([50; cellfun(@(x) str2num(strrep(strrep(x, 'R',''), 'L','-')), cells)]), 100) == 0))
```

For Part 2, my trick was to unroll each rotation of Ln or Rn into n rotations of -1 or +1, respectively. A slightly more cursed one-liner:

```
length(find(mod(cumsum([50; cell2mat(cellfun(@(x) ((substr(x,1,1)=='R')*2-1)*ones(str2num(substr(x,2)), 1), cells, 'UniformOutput',false))]), 100) == 0))
```