Here’s how you can play D&D with just that little six-sided dice that came in your monopoly box.

(I think I”ve got the approach with the fewest expected rerolls, there are still going to be some but it will do in a pinch (or you could just buy my dice app I guess…)) #Dice #DnD #ttrpg

To be clear, I do not recommend doing this. It will slow the game down a bunch.

But, the math works, the results will be fair.

Okay so I thought of a way to reduce the expected roll to 1.333etc when trying to get a d4 result, but it’s not as straightforward to describe and complicates the process. OTOH it does also cap the rolls for that part to 2.

Basically:
If you roll 1-4, that’s the result, if not remember the result and roll again.
If the second roll isn’t 1-4, then compare first and second rolls:
5,5 = 1
5,6 = 2
6,5 = 3
6,6 = 4

@Sophie You can do this on the d8 to guarantee three rolls or less too
@dx yup, and the d20
@Sophie I’m not sure you can guarantee the d20 in any number of rolls. Or d10. Because 6^N is never divisible by 10.
@Sophie (That is of course theoretically speaking. I would stake any amount of money on a fair d20 eventually resolving under this scheme, and quickly too)
@dx I think you’re right, I’m very close to getting nerd-sniped by trying to think of a guaranteed limit to rerolls but I’m going to just do myself a favour and… not. lol
@Sophie Having just gone down that garden path myself, I’ll save you the trouble: I’m pretty sure to guarantee number of rolls you need 6^N to be divisible by the number of faces on the simulated die, where N is any integer. If you consider each additional roll as adding x6 leaf nodes per existing leaf node to a graph of possibilities, that makes it easier to visualize. (1/2)

Since 6^N always ends in 6, it can never be cleanly divisible by 5, so there is no way to guarantee a map.

I wondered about d7 whether that’s possible with d6 and guaranteeing number of rolls, because 7xN sometimes ends in 6, but I tested up to 5000d6 without luck. (2/2)

@dx oh right sorry, I just meant it could trim the expected rolls by capping the first part (rolling for the quarter)
@Sophie is keeping the probability of rolling any given number constant important here?
@swiftcoder sorry for the delayed response, my server filtered your reply.
Anyway the answer is yes, I wanted a fair d6 to be equivalent to other fair dice

@Sophie I love how clever that is!

Still, the thought that you need to roll a bigger die twice to get a smaller die's result disturbed me, so I kept thinking:

What if we use the results on the sides of the die, instead of just the one at the top? That way, on a 5 or 6 top result, you look at the side that's facing you (push the die back with a straight object to disambiguate, if needed). The possibilities would be:

* On a 6: 2, 3, 4, 5 - treat 5 as a 1
* On a 5: 1, 3, 4, 6 - treat 6 as a 2

@noc that’s cool, I like it a lot!
@Sophie For d4/d8 can also flip coins of different denominations. It’s more things, but things you probably have around.

@Sophie To elaborate, coins side values of 0/4, 0/2, 1/2 will give a d8 (basically just binary bit encoding without allowing a 0 in the smallest bit because dice don’t usually have zeroes)

I wonder if anyone’s made an rpg that uses only coins and uses their denominations, like flip some coins and add up the monetary value of all the face up ones

@dx that is a really interesting idea! And I am definitely a fan of binary dice lol https://dice.camp/@Sophie/109348141283773504
Sophie 🎲🧩🏳️‍⚧️ (@[email protected])

Attached: 1 image Oh I forgot to include these in the pic, a d1024 (ten binary dice)

Dice.camp

@Sophie my vintage copy of "What Is Dungeons and Dragons" had a very similar method.

https://www.goodreads.com/book/show/2271678.What_is_Dungeons_and_Dragons_

What is Dungeons and Dragons?

A guide to the phenomenal fantasy game, "Dungeons and D…

Goodreads

@Sophie If you want to use a D6 as a D6, you can consult my patented random diceroll table over here: https://meow.social/@Owlor/113981667963711204 (a shitpost I made as a really stupid joke)

I'm gonna bookmark this post as reference cus I'm always on the lookout for ways to stretch using only a couple of D6es to its limit (these days polyhedral dice or dice rollers aren't that hard to come by, but as a nod to both japanese and indie TTRPG tradition I like to use D6es only as much as possible so my games are playable by just raiding an average board game shelf).

Owlor (@[email protected])

Content warning: not screenreader friendly

meow.social - the meowstodon instance for creatures fluffy, scaly and otherwise
@Sophie Made me remember that I had this in a document. If the sides are relabeled, then it's actually quite fast to read (sum) – no rules to remember. Some types of numbers are easier to sum than others so in cases where several methods are possible one might be preferable. The dice can be arranged into colour groups to prevent mixing. The "smallest" (least significant die) can start from zero or not. Might make sense with my red D100 series.
@Sophie If you have a number d6 instead of a pip d6 you can use orientation to shrink some of these down further. For example, for a d12, if the number is upside down it’s 1-6 and right side up 7-12.

@dx okay so I got nerd-sniped anyway lol, and your orientation thought is the best I can do. A d6 can be a d5 by:

1-5 is top face: job done
6 is top face: the 2 face is on the side, measure the angle it points, it’ll fall somewhere in a fifth lol

(If you measure a side face’s direction then even pipped dice are fine)

@Sophie Just bought your dice app (even though I already have two others) because this was such a delightful problem to think about today. Thanks!
@dx hooray, I hope you enjoy it! (You might find extra fun in the dice expressions and the testing of them! https://sophiehoulden.com/dice/documentation/expressiontesting.html )
Sophie's Dice - Expression Testing

Documentation for Expression Testing in Sophie's Dice

Sophie's Dice - Expression Testing
@Sophie Oh man you got the good dice here. Teetotums! Astragalus! I should have gotten this app long ago
@Sophie do you have the opposite of this (player has a polyset but needs to roll several d6)?
@polychromata I think then it’s simplest to just use a d12 (for any result over 6, you just subtract 6)