To be clear, I do not recommend doing this. It will slow the game down a bunch.
But, the math works, the results will be fair.
To be clear, I do not recommend doing this. It will slow the game down a bunch.
But, the math works, the results will be fair.
Okay so I thought of a way to reduce the expected roll to 1.333etc when trying to get a d4 result, but it’s not as straightforward to describe and complicates the process. OTOH it does also cap the rolls for that part to 2.
Basically:
If you roll 1-4, that’s the result, if not remember the result and roll again.
If the second roll isn’t 1-4, then compare first and second rolls:
5,5 = 1
5,6 = 2
6,5 = 3
6,6 = 4
Since 6^N always ends in 6, it can never be cleanly divisible by 5, so there is no way to guarantee a map.
I wondered about d7 whether that’s possible with d6 and guaranteeing number of rolls, because 7xN sometimes ends in 6, but I tested up to 5000d6 without luck. (2/2)