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Why would you multiple Cohen's d by sqrt(2) to get a "generic d"? ๐คทโโ๏ธ
See here:
.. the sample mean was 48.19, the expected age in the population was 50, so the difference would be 48.19 - 50 = -1.81. The standard deviation was 17.69, so Cohen's d becomes: d = -1.81 / 17.69 = 0.10. Cohen suggests to multiply this with the square root of 2, to get a generic d... (Cohen, 1988, p. 40).