ยซGiven the Moonโ€™s weaker gravity (and movement differences between it and Earth), time moves slightly faster there. So an Earth-based clock on the lunar surface would appear to gain an average of 58.7 microseconds per Earth day. As the US and other countries plan Moon missions to research, explore and (eventually) build bases for permanent residence, using a single standard will help them synchronize technology and missions requiring precise timing.ยป

#Moon
#Time
#LTC

https://www.engadget.com/the-white-house-tells-nasa-to-create-a-new-time-zone-for-the-moon-193957377.html

The White House tells NASA to create a new time zone for the Moon

On Tuesday, The White House published a policy memo directing NASA to create a new time standard for the Moon by 2026. Coordinated Lunar Time (LTC) will...

Engadget

@JProl

It's not hard to snicker about amateurs. I've given you a boost for having been so keen to point out Will Shanklin's <em>"apparent gain"</em> instead of <a href="https://www.whitehouse.gov/wp-content/uploads/2024/04/Celestial-Time-Standardization-Policy.pdf">Arati Prabhakar's <em>"apparent loss"</em> ... and for keeping the attention, too.

Coming up with some (presumably) correct + still reasonably short description seems more challenging (to me). My best attempt so far:

<blockquote>
<b>If</b> two astronauts had met "somewhere in (cislunar) space", and subsequently separated from each other,

- with one astronaut venturing on to land on the lunar surface, and

- the other astronaut returning to the Earth's surface,

such that (as may happen in selected trials)

- it takes both astronauts exactly equally long, resp., from separating until reaching (halting on) the Moon, or on Earth,

after some (not further specified) while, either astronaut perhaps being prompted by suitable prearranged signals,

- both again take off from Earth, and from the Moon, resp., and they meet again "somewhere in (cislunar) space", where again (trials must be selected such that)

- the duration of one astronaut from her take-off until the re-union meeting

- happens to be exactly equal to the duration of the other astronaut from his take-off until being together again

<b>then/therefore</b>

the astronaut who had stayed on the lunar surface had remained there
(pretty much) <b>exactly</b>
\[\left(1 + \frac{58.7 * 10^{-6}}{86400}\right) \approx (1 + 6.8 * 10^{-10})\]
<b>times as long as</b>
the astronaut who had stayed on the the surface of the Earth had remained there.

</blockquote>

So: Good luck, #NASA ! ...

#LTC #LunarTime #Duration #Rate #Clock #Relativity #Spacetime

@JProl

Why on Earth is basic formatting

https://docs.joinmastodon.org/spec/activitypub/#sanitization

still not supported for my previous post/toot ?!???

Is this not running v4.2.7 ?? ...

#MastodonHelp #MathstodonHelp
#FormattingHelp

ActivityPub - Mastodon documentation

A decentralized social networking protocol based upon the ActivityStreams 2.0 data format and JSON-LD.

@MisterRelativity

I don't know if your instance supports html formatting, although I think it does support LaTex.

You can ask the admin @christianp