@JProl
It's not hard to snicker about amateurs. I've given you a boost for having been so keen to point out Will Shanklin's <em>"apparent gain"</em> instead of <a href="https://www.whitehouse.gov/wp-content/uploads/2024/04/Celestial-Time-Standardization-Policy.pdf">Arati Prabhakar's <em>"apparent loss"</em> ... and for keeping the attention, too.
Coming up with some (presumably) correct + still reasonably short description seems more challenging (to me). My best attempt so far:
<blockquote>
<b>If</b> two astronauts had met "somewhere in (cislunar) space", and subsequently separated from each other,
- with one astronaut venturing on to land on the lunar surface, and
- the other astronaut returning to the Earth's surface,
such that (as may happen in selected trials)
- it takes both astronauts exactly equally long, resp., from separating until reaching (halting on) the Moon, or on Earth,
after some (not further specified) while, either astronaut perhaps being prompted by suitable prearranged signals,
- both again take off from Earth, and from the Moon, resp., and they meet again "somewhere in (cislunar) space", where again (trials must be selected such that)
- the duration of one astronaut from her take-off until the re-union meeting
- happens to be exactly equal to the duration of the other astronaut from his take-off until being together again
<b>then/therefore</b>
the astronaut who had stayed on the lunar surface had remained there
(pretty much) <b>exactly</b>
\[\left(1 + \frac{58.7 * 10^{-6}}{86400}\right) \approx (1 + 6.8 * 10^{-10})\]
<b>times as long as</b>
the astronaut who had stayed on the the surface of the Earth had remained there.
</blockquote>
So: Good luck, #NASA ! ...
#LTC #LunarTime #Duration #Rate #Clock #Relativity #Spacetime