user8e8f87eWhat do you prefer?
```
\a b -> (a, Just b)
```
or:
```
(. Just) . (,)
```
and why?
I prefer the lambda version
Pointfree or die
Poll ended at .
das-g@user8e8f87c The pointfree variant here is not (yet?) easily comprehensible to me, probably because it combines sections of higher order operator (.) with a constructor. I know all the components needed to understand it, but I need to do too much mental gymnastics to wrap my head around it, whereas with the lambda version it's to me immediately apparent what it does.
@das_g `(. Just) . (,) $ a == (. Just) $ (,) a == (. Just) (a,) == (a,) . Just`
Andres Löh@user8e8f87c Is this a serious question? The first.
@kosmikus I was about to have the second one in my code, but I had mercy with my future me and decided against it.
What I like about it is that it helps my understand that `a` can be a function in:
```
a -> b == a -> (c -> d)
```
With this in mind it is not that hard to understand.
Oriel Jutty 
curry (fmap Just)
@barubary Haha, nice!