Bash has a way to specify strings with escaped characters like so: $'\r\n' which gives a string containing carriage return and newline characters.
The `read` built-in can take a delimiter with the -d flag. Combining these lets you use a null character: read -d $'\0'
Useful in some of the same places you might use xargs(1).
find . -name ... -print0 | while read -d $'\0'; do ./foo "$REPLY"; done
@Viss you can kinda do it with string substitution. This will remove a single trailing newline: ${foo%[$'\n']}
Or a trailing space: ${foo%[[:space:]]}
The replacement in a % or %% substitution is like a file glob, not a regexp, so you can't say one-or-more.
@snowchyld because I don't know how to do this with xargs
| while read -d $'\0'; do
./foo "${REPLY%.app}" |& grep -q thing && echo $REPLY; done
egyp7
Viss
snowchyld