CharlotteWhat should happen if you attempt to roll a die with zero sides?
Error ("Cannot roll a die with zero sides.")
Outcome is zero
Poll ended at .
unnick@CenTdemeern1 getting an outcome of 0 implies that the die has at least one side with 0 on it
@CenTdemeern1 rolling a die isnt the same as summing numbers, and edge cases can be different.
ill try another explanation: if you have a die (for example a normal d6) and remove one of its sides (for example, the 4 side), then if you roll the modified die you can never* roll a 4, and the modified die cant roll new numbers that werent in the original die, like 8. (*only talking about dies without duplicate sides). now take a die that has just one side labelled with the number 7, so every time you roll it you get a 7. after you remove the 7 side, you get a zero sided die. you cant roll a 7 since that side was removed, you cant roll a 0 or any other number since it wasnt in the original die. so you cant really roll it at all
ill try another explanation: if you have a die (for example a normal d6) and remove one of its sides (for example, the 4 side), then if you roll the modified die you can never* roll a 4, and the modified die cant roll new numbers that werent in the original die, like 8. (*only talking about dies without duplicate sides). now take a die that has just one side labelled with the number 7, so every time you roll it you get a 7. after you remove the 7 side, you get a zero sided die. you cant roll a 7 since that side was removed, you cant roll a 0 or any other number since it wasnt in the original die. so you cant really roll it at all
Mai 
@unnick @CenTdemeern1 Another angle to see this would be set theroy; like a normal d6 would conform to the set {1, 2, 3, 4, 5, 6} while your special die with only one face showing seven would be the set {7}. A true zero-sided set would therefor be the empty set ∅ / {}.
Now we define the action of rolling to picking a random entry of the set... however I'm unsure what this means in the case of ∅:
We could argue that randomly picking is reducing the set to just a set by throwing our all other numbers, this would mean that a d6 would be reduced to
{4}(if you roll a 4); in the same manner, rolling ∅ would mean the result still is ∅ since we cant reduce further.On the other hand we can go the normal way and say it's not reducing the set but producing a number, but numbers themselv can be represented using sets by converting the number (i.e. 3) into a series of nested sets build by their previous components:
0 = ∅
1 = {0} = {∅}
2 = {0,1} = {∅, {∅}}
3 = {0,1,2} = {∅, {∅}, {∅, {∅}}}
(Called Zermelo-Fraenkel set theory)
... so ultemately I think the right answer would be ∅? (I'm not a mathematician, I just like nerdy stuff and happen to know about set theory bc. of uni, but I'm happy to be proven wrong)