I dunno
Obviously the answer is 2+x(y)
And even if you don’t simplify it to y the end result is the same
2+x(y-z) = 2+xy-xz
I don’t know why, but this was intuitively my first approach. Eve though it’s much simpler than that.

I don’t know why, but this was intuitively my first approach

Because that’s what we teach students to do, though technically it should be (xy-xz)

I feel like I am getting trolled

Isn’t 17 the actual right answer?

Exactly
So it’s just an unfunny meme?
As most memes are.

I think it’s meant to play with your expectations. Normally someone’s take being posted is to show them being confidently stupid, otherwise it isn’t as interesting and doesn’t go viral.However, because we’re primed to view it from that lens, we feel crazy to think we’re doing the math correctly and getting the β€œwrong answer” from what we assume is the β€œconfident dipshit”.

There’s layers beyond the superficial.

I fell for it. It’s crazy to think how heavily I’ve been trained to believe everything I see is wrong in the most embarrassing and laughable way possible. That’s pretty depressing if you think about it.
Not even a meme.
More like a sad realization of the state of (un)education in some parts of the so-called civilized world.
You laugh not to cry.
It’s engagement bait.
There is no answer. Because there is no question.
That is a problem, tho
I know the solution

Because there is no question

So Maths test says β€œ2+3 ____”, and you write β€œthat’s not a question” on the blank line?? πŸ˜‚

Inside the parens first, so it becomes 2 + 5*3

Then tou do multiplication before addition, so 2 + 15

Then addition, so 17

Yeah I know that. But I was feeling confused as to why it was here. That’s why I was feeling trolled, because it made me doubt basic math for being posted in a memes community.
Because OP posts garbage to all the meme communities.

This shit take got deleted right in front of my eyes

The system works

They did the joke wrong. To do it right you need to use the Γ· symbol. Because people never use that after they learn fractions, people treat things like a + b Γ· c + d as

a + b ----- c + d

Or (a + b) Γ· (c + d) when they should be treating it as a + (b Γ· c) + d.

That’s the most common one of these β€œtroll math” tricks. Because notating as

a + b + d - c

Is much more common and useful. So people get used to grouping everything around the division operator as if they’re in parentheses.

Or
12 / 2(6) And trying to argue this is 36.

Well, now you might be running into syntax issues instead of PEMDAS issues depending on what they’re confused about. If it’s 12 over 2*6, it’s 1. If it’s 12 Γ· 2 x 6, it’s 36.

A lot of people try a bunch of funky stuff to represent fractions in text form (like mixing spaces and no spaces) when they should just be treating it like a programmer has to, and use parenthesis if it’s a complex fraction in basic text form.

The P in PEMDAS means to solve everything within parentheses first; there is no β€œdistribution” step or rule that says multiplying without a visible operator other than parentheses comes first. So yes, 36 is valid here. It’s mostly because PEMDAS never shows up in the same context as this sort of multiplication or large fractions

The P in PEMDAS means to solve everything within parentheses first

and without a(b+c)=(ab+ac), now solve (ab+ac)

there is no β€œdistribution” step or rule

It’s a LAW of Maths actually, The Distributive Law.

that says multiplying without a visible operator

It’s not β€œMultiplying”, it’s Distributing, a(b+c)=(ab+ac)

So yes, 36 is valid here

No it isn’t. To get 36 you have disobeyed The Distributive Law, thus it is a wrong answer

It’s mostly because

people like you try to gaslight others that there’s no such thing as The Distributive Law

Are you under the impression that atomizing your opponents statements and making a comment about each part individually without addressing the actual point (how those facts fit together) is a good debate tactic? Because it seems like all you’ve done is confuse yourself about what I was saying and make arguments that don’t address it.

addressing the actual point (how those facts fit together)

I did address the actual point - see Maths textbooks

all you’ve done is confuse yourself

I’m not confused at all. I’m the one who knows the difference between Distribution and Multiplication.

what I was saying

You lied about there being no such thing as β€œthe Distribution step” (Brackets), proven wrong by the textbooks

make arguments that don’t address it.

Textbooks talking about The Distributive Law totally addresses your lie that no such step exists.

Never mind that some of those micro-rebuttals aren’t even correct

You think Maths textbooks aren’t correct?? πŸ˜‚

I have said why this style of debate is bad in greater detail here: lemmy.world/post/39377635/21030374

But to make a pointless effort to address your actual point, yes distribution exists, no it is not a step in PE(MD)(AS). Again, you have not understood my point because you categorically fail to engage with any argument. I don’t think you even understand what it means to do so. I will not respond further to either thread.

I dunno - Lemmy.World

Lemmy

I have said why this style of debate is bad in greater detail here: lemmy.world/post/39377635/21030374

Which I debunked here

no it is not a step in PE(MD)(AS)

So… you’re saying the β€œP” step in PEMDAS isn’t a step in PEMDAS?? This is hilarious given you were just talking about contradictions πŸ˜‚

Again, you have not understood my point

Maybe because saying the β€œP” step in PEMDAS isn’t a step in PEMDAS makes no sense at all πŸ˜‚

you categorically fail to engage with any argument.

No, I comprehensively debunked all of your points and deflections. πŸ˜‚

I don’t think you even understand what it means to do so

says person who keeps avoiding the textbook screenshots and worked examples proving them wrong

I will not respond further to either thread

Yay! Don’t let the door hit you on the way out πŸ˜‚

I dunno - Lemmy.World

Lemmy

Parentheses means evaluating the things inaide the parentheses you nimrod

Parentheses means evaluating the things inside the parentheses you nimrod

Only if you’re still in Elementary school. How old are you anyway? Here’s a high school Algebra book, you know, after students have been taught The Distributive Law…

Now that’s a good troll math thing because it gets really deep into the weeds of mathematical notation. There isn’t one true order of operations that is objectively correct, and on top of that, that’s hardly the way most people would write that. As in, if you wrote that by hand, you wouldn’t use the / symbol. You’d either use Γ· or a proper fraction.

It’s a good candidate for nerd sniping.

Personally, I’d call that 36 as written given the context you’re saying it in, instead of calling it 1. But I’d say it’s ambiguous and you should notate in a way to avoid ambiguities. Especially if you’re in the camp of multiplication like a(b) being different from ab and/or a Γ— b.

Nerd Sniping

xkcd

There isn’t one true order of operations that is objectively correct

Yes there is, as found in Maths textbooks the world over

that’s hardly the way most people would write that

Maths textbooks write it that way

you wouldn’t use the / symbol

Yes you would.

You’d either use Γ·

Same same

It’s a good candidate for nerd sniping.

Here’s one I prepared earlier to save you the trouble

I’d call that 36

And you’d be wrong

as written given the context you’re saying it in

The context is Maths, you have to obey the rules of Maths. a(b+c)=(ab+ac), 5(8-5)=(5x8-5x5).

But I’d say it’s ambiguous

And you’d be wrong about that too

you should notate in a way to avoid ambiguities

It already is notated in a way that avoids all ambiguities!

Especially if you’re in the camp of multiplication like a(b)

That’s not Multiplication, it’s Distribution, a(b+c)=(ab+ac), a(b)=(axb).

being different from ab

Nope, that’s exactly the same, ab=(axb) by definition

and/or a Γ— b

(axb) is most certainly different to axb. 1/ab=1/(axb), 1/axb=b/a

πŸ’‘πš‚π—†π–Ίπ—‹π—π—†π–Ίπ—‡ π™°π—‰π—‰π—ŒπŸ“± (@[email protected])

1/3 #MathsMonday Order of operations thread index #Mathematics #Maths #Math Introduction https://dotnet.social/@SmartmanApps/110807192608472798 1 The Distributive Law #DontForgetDistribution https://dotnet.social/@SmartmanApps/110819283738912144 2 Terms #MathsIsNeverAmbiguous https://dotnet.social/@SmartmanApps/110846452267056791 3 Factorising<->The Distributive Law https://dotnet.social/@SmartmanApps/110886637077371439 4 implicit multiplication, mnemonics https://dotnet.social/@SmartmanApps/110925761375035558 5 1917 (i) - Left Associativity https://dotnet.social/@SmartmanApps/110965810374299599 6 1917 (ii) - Lennes' letter (Terms and operators) https://dotnet.social/@SmartmanApps/111005247356655843 ...

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Please read this section of Wikipedia which talks about these topics better than I could. It shows that there is ambiguity in the order of operations and that for especially niche cases there is not a universally accepted order of operations when dealing with mixed division and multiplication. It addresses everything you’ve mentioned.

en.wikipedia.org/wiki/Order_of_operations#Mixed_d…

There is no universal convention for interpreting an expression containing both division denoted by β€˜Γ·β€™ and multiplication denoted by β€˜Γ—β€™. Proposed conventions include assigning the operations equal precedence and evaluating them from left to right, or equivalently treating division as multiplication by the reciprocal and then evaluating in any order;[10] evaluating all multiplications first followed by divisions from left to right; or eschewing such expressions and instead always disambiguating them by explicit parentheses.[11]

Beyond primary education, the symbol β€˜Γ·β€™ for division is seldom used, but is replaced by the use of algebraic fractions,[12] typically written vertically with the numerator stacked above the denominator – which makes grouping explicit and unambiguous – but sometimes written inline using the slash or solidus symbol β€˜/’.[13]

Multiplication denoted by juxtaposition (also known as implied multiplication) creates a visual unit and is often given higher precedence than most other operations. In academic literature, when inline fractions are combined with implied multiplication without explicit parentheses, the multiplication is conventionally interpreted as having higher precedence than division, so that e.g. 1β€Š/β€Š2n is interpreted to mean 1β€Š/β€Š(2 · n) rather than (1β€Š/β€Š2) · n.[2][10][14][15] For instance, the manuscript submission instructions for the Physical Review journals directly state that multiplication has precedence over division,[16] and this is also the convention observed in physics textbooks such as the Course of Theoretical Physics by Landau and Lifshitz[c] and mathematics textbooks such as Concrete Mathematics by Graham, Knuth, and Patashnik.[17] However, some authors recommend against expressions such as aβ€Š/β€Šbc, preferring the explicit use of parenthesis aβ€Š/β€Š(bc).[3]

More complicated cases are more ambiguous. For instance, the notation 1β€Š/β€Š2Ο€(a + b) could plausibly mean either 1β€Š/β€Š[2π · (a + b)] or [1β€Š/β€Š(2Ο€)] · (a + b).[18] Sometimes interpretation depends on context. The Physical Review submission instructions recommend against expressions of the form aβ€Š/β€Šbβ€Š/β€Šc; more explicit expressions (aβ€Š/β€Šb)β€Š/β€Šc or aβ€Š/β€Š(bβ€Š/β€Šc) are unambiguous.[16]

6Γ·2(1+2) is interpreted as 6Γ·(2Γ—(1+2)) by a fx-82MS (upper), and (6Γ·2)Γ—(1+2) by a TI-83 Plus calculator (lower), respectively.

This ambiguity has been the subject of Internet memes such as β€œ8 ÷ 2(2 + 2)”, for which there are two conflicting interpretations: 8 ÷ [2 · (2 + 2)] = 1 and (8 ÷ 2) · (2 + 2) = 16.[15][19] Mathematics education researcher Hung-Hsi Wu points out that β€œone never gets a computation of this type in real life”, and calls such contrived examples β€œa kind of Gotcha! parlor game designed to trap an unsuspecting person by phrasing it in terms of a set of unreasonably convoluted rules”.[12]

Order of operations - Wikipedia

Please read this section of Wikipedia which talks about these topics better than I could

Please read Maths textbooks which explain it better than Joe Blow Your next Door neighbour on Wikipedia. there’s plenty in here

It shows that there is ambiguity in the order of operations

and is wrong about that, as proven by Maths textbooks

especially niche cases there is not a universally accepted order of operations when dealing with mixed division and multiplication

That’s because Multiplication and Division can be done in any order

It addresses everything you’ve mentioned

wrongly, as per Maths textbooks

Multiplication denoted by juxtaposition (also known as implied multiplication)

Nope. Terms/Products is what they are called. β€œimplied multiplication” is a β€œrule” made up by people who have forgotten the actual rules.

s often given higher precedence than most other operations

Always is, because brackets first. ab=(axb) by definition

1β€Š/β€Š2n is interpreted to mean 1β€Š/β€Š(2 · n)

As per the definition that ab=(axb), 1/2n=1/(2xn).

[2][10][14][15]

Did you look at the references, and note that there are no Maths textbooks listed?

the manuscript submission instructions for the Physical Review journals

Which isn’t a Maths textbook

the convention observed in physics textbooks

Also not Maths textbooks

mathematics textbooks such as Concrete Mathematics by Graham, Knuth, and Patashnik

Actually that is a Computer Science textbook, written for programmers. Knuth is a very famous programmer

More complicated cases are more ambiguous

None of them are ambiguous.

the notation 1β€Š/β€Š2Ο€(a + b) could plausibly mean either 1β€Š/β€Š[2π · (a + b)]

It does as per the rules of Maths, but more precisely it actually means 1β€Š/β€Š(2Ο€a + 2Ο€b)

or [1β€Š/β€Š(2Ο€)] · (a + b).[18]

No, it can’t mean that unless it was written (1β€Š/β€Š2Ο€)(a + b), which it wasn’t

Sometimes interpretation depends on context

Nope, never

more explicit expressions (aβ€Š/β€Šb)β€Š/β€Šc or aβ€Š/β€Š(bβ€Š/β€Šc) are unambiguous

a/b/c is already unambiguous - left to right. πŸ™„

Image of two calculators getting different answers

With the exception of Texas Instruments, all the other calculator manufacturers have gone back to doing it correctly, and Sharp have always done it correctly.

6Γ·2(1+2) is interpreted as 6Γ·(2Γ—(1+2))

6Γ·(2x1+2x2) actually, as per The Distributive Law, a(b+c)=(ab+ac)

(6Γ·2)Γ—(1+2) by a TI-83 Plus calculator (lower)

Yep, Texas Instruments is the only one still doing it wrong

This ambiguity

doesn’t exist, as per Maths textbooks

β€œ8 ÷ 2(2 + 2)”, for which there are two conflicting interpretations:

No there isn’t - you MUST obey The Distributive Law, a(b+c)=(ab+ac)

Mathematics education researcher Hung-Hsi Wu points out that β€œone never gets a computation of this type in real life”

And he was wrong about that. πŸ™„

calls such contrived examples

Which notably can be found in Maths textbooks

πŸ’‘πš‚π—†π–Ίπ—‹π—π—†π–Ίπ—‡ π™°π—‰π—‰π—ŒπŸ“± (@[email protected])

1/3 #MathsMonday Order of operations thread index #Mathematics #Maths #Math Introduction https://dotnet.social/@SmartmanApps/110807192608472798 1 The Distributive Law #DontForgetDistribution https://dotnet.social/@SmartmanApps/110819283738912144 2 Terms #MathsIsNeverAmbiguous https://dotnet.social/@SmartmanApps/110846452267056791 3 Factorising<->The Distributive Law https://dotnet.social/@SmartmanApps/110886637077371439 4 implicit multiplication, mnemonics https://dotnet.social/@SmartmanApps/110925761375035558 5 1917 (i) - Left Associativity https://dotnet.social/@SmartmanApps/110965810374299599 6 1917 (ii) - Lennes' letter (Terms and operators) https://dotnet.social/@SmartmanApps/111005247356655843 ...

dotnet.social
If you believe the article is incorrect, submit your corrections to Wikipedia instead of telling me.

If you believe the article is incorrect, submit your corrections to Wikipedia

You know they’ve rejected corrections by actual Maths Professors right? Just look for Rick Norwood in the talk section. Everyone who knows Maths knows Wikipedia is wrong, and looks in the right place to begin with - Maths textbooks

Again, if you have a problem with Wikipedia, take it up with Wikipedia.

Again, if you have a problem with Wikipedia, take it up with Wikipedia

You’ve made the mistake of thinking they care. Again, look for Rick Norwood in the Talk sections, an actual Maths professor (bless him for continually trying to get them to correct the mistakes though)

Take it up with them if you have a problem with them.

Take it up with them if you have a problem with them

I see you’re not even reading what I said. No wonder you don’t know how to do Maths…

I did read everything you said and I do know how to do math. I hope you are able to enact the change you want to see in Wikipedia and the article. Good luck.

I did read everything you said

Clearly you didn’t, given you keep telling me to take it up with Harvard/Wiki

enact the change you want to see in Wikipedia

See?? There you go again ignoring what I told you about Wikipedia πŸ™„

I haven’t ignored anything you said. I’m telling you that if you have a problem with those that you should contact them to fix them.

I haven’t ignored anything you said.

You’ve ignored everything I’ve said about Wikipedia.

I’m telling you that if you have a problem with those that you should contact them to fix them

and you have again ignored what I told you about them πŸ™„

It’s funny that you define β€œignore” as β€œnot doing what you tell someone to” because by that definition you’ve been ignoring me too. Go edit the article if you feel this strongly.
Treat a + b/c + d as a + b/(c + d) I can almost understand, I was guilty of doing that in school with multiplication, but auto-parenthesising the first part is really crazy take, imo

That’s a really odd way to parse it.

a + b ----- c + b

Treat a + b/c + d as a + b/(c + d)

No don’t. That rule was changed more than 130 years ago. a+b/c+d=a+(b/c)+d, Division before Addition

Because people never use that after they learn fractions,

Yes they do, because not every division is a fraction

math.berkeley.edu/~wu/order5.pdf

I already said he was wrong about that. Quoting him saying it doesn’t change that he’s wrong about it

Take it up with Berkeley then.

Take it up with Berkeley then

What for? You’re only the second person ever to have quoted him. You’re not the first person to refuse to look in Maths textbooks though πŸ™„

Take it up with Berkeley.

Take it up with Berkeley

Says person refusing to look in Maths textbooks πŸ˜‚

I cannot stress this enough. If you have a problem with that, contact the author or Berkeley, not me.

I cannot stress this enough. If you have a problem with that, contact the author or Berkeley, not me

I cannot stress this enough - look in Maths textbooks, not random University blogs πŸ˜‚