Wooo, another nerd snipe:
Find the limit of the xth root of x as x approaches infinity.
Not too horrible, but definitely a smidge of fun.
Wooo, another nerd snipe:
Find the limit of the xth root of x as x approaches infinity.
Not too horrible, but definitely a smidge of fun.
note2self: proxmox-helper-scripts nur noch dosiert konsumieren.
Ich #nerdsnipe mich IMMER mehrfach selbst(!!!)
Wenn man mit Vorsatz aber auch NIX fertig kriegen will, ist das allerdings ein guter Weg.
neuster take: #birdnetgo
24/7 Vogelstimmenerkennung, UND man muss sich noch nen esp32 mit Mikro basteln und inn Garten baumeln.
#netbird ist ja komplett out of control!
Ich wollte per #headscale meine VPS mit meiner homeprod verdrahten.
Netbird ist alles was tailscale per SaaS sein kann, aber #selfhosted.
Das setup ist irre. FW auf auf den relevanten Ports, DNS aufsetzen, script anwerfen, Fertig.
Wer wie ich keine Lust auf externe Infrastruktur ausserhalb der eigenen Kontrolle hat und site2site braucht, ich glaube besser gehts nich.
#diy #homelab #overlaynetwork #wireguard
danke @staticvoid für den #nerdsnipe
Another day, another math problem. Was browsing the Internet and ran across one of those math social media posts that asked to solve `8^x + 2^x = 30` and decided to go all the way down the rabbit hole on the solution. Also learned a bit about spacing in math mode for LaTeX as well...
Relaxing at home and got nerd sniped again via YouTube. Looked interesting enough to give it a shot though the thumbnail was more than a bit misleading as they used `n` instead of `x` which has certain connotations associated with it.
I mean, what are the odds?
Nerd sniped myself this time: after getting sniped yesterday with showing that for primes `p >= 5` that `24 | p^2 - 1`, I decided to look at primes `p, q` where `p, q >= 5` and see if `24 | p^2 - q^2`.
Yay, got nerd sniped with another math problem. I made it a smidge more difficult than it should've been, but I'm happy that I got the correct answer eventually.
The problem: Given `1 / tan(x) = tan(1 / x)`, solve for `x`.