@drdrang I like the hard way. There’s a handy “solving formula” for geometric series like the one in the 2nd to last equation: you have a series in the form of

∑ a r^i

as i goes 1 to inf, where a=1 and r=1/(3+2√2). The sum can be computed by

a/(1-r).

To make it work in this case, write the series as if starting from i=0 by subtracting an “a r^i” at i=0:

a/(1–r) – a r^0 = a/(1–r) – 1.

That in turn should make the full expression evaluate to π.

@cliffwade Idk why bother, unless you have something specific you need it for. It’s best for installing programming languages and command line tools etc that you’d have to compile yourself otherwise. If you’re not into stuff like that, there’s a high chance many of your apps aren’t even available.

However, it’s easy to use and has a handy way of updating everything at once, so if you find enough apps on it, then sure, why not. There’s a subset of “normal apps” on it too.