100 000 Years to Coinflip 1/10 What if we keep trying? Not a sure win—that’s impossible—but just a coin flip, a 50–50 chance. 🎯 #Emberhart#CoinFlipOdds#LongGame
100 000 Years to Coinflip 2/10 Buy 5 tickets every Christmas. Do it year after year. The question becomes: how long until there’s a 50% chance of winning at least once? ⏳ #CumulativeProbability#TryingAgain#MathLimits
100 000 Years to Coinflip 3/10 Using cumulative probability, the chance of never winning over n years is (0.999995)ⁿ. The math starts here. 🧮 #ComplementRule#NoSureWins#RiskMath
100 000 Years to Coinflip 4/10 Set the probability of “no wins” to 50%. That means the probability of winning at least once is also 50%. ⚖️ #FiveTickets#AnnualPlay#ProbabilityCurve
100 000 Years to Coinflip 5/10 Solve it with logarithms and you get the answer: about 138,629 years of buying 5 tickets per year. 📐 #Logarithms#FiftyPercent#TimeScale
100 000 Years to Coinflip 7/10 What if we only give it 20 years? To reach 50% in that time would require ~34,657 tickets per year. 💸 #TwentyYearPlan#CapitalIntensity#EuroMath
100 000 Years to Coinflip 9/10 Including second-tier prizes helps a bit: odds improve to 1 in 40,000 with 5 tickets—but they’re still poor. 🎲 #SecondTierPrizes#ImprovedOdds#StillUnlikely