Note: I'm really unsure, with my hack quasiquote, what to call the "$" operator. It's not quasiquote— quasiquote is my "sub" function. I think "$" is the operator LISPs call "unquote", but I don't want to say that because I have an "unquote" function in my stdlib. I was gonna call it "pseudoquote", but I'm told LISP gives that word a special meaning too.

I am inclined to call $ "substitute". $ for $ubstitute. Might annoy the LISP heads, but much about this language will

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