A Riemann surface is not a special case of a Riemannian manifold, which is a manifold equipped with a Riemannian metric. A Riemannian metric is not a special case of a metric. You can use a Riemannian metric to define a metric though. A Riemannian metric is an equipment of an inner product to the tangent space at each point of the manifold. With this, you can define the length of a tangent vector as the inner product with itself (sqrt-ed). So then you can compute the length of a curve in the manifold as integrating over the curve's tangent vectors. Now we can define the distance between two points in the manifold as the infimum of lengths of curves that connect them.

Theorem: The topology generated by this metric is the same as the original topology on the manifold.

@Joemoeller I mean the most important part you kind of suppressed, namely that the inner products need to vary smoothly with respect to the metric. Which i think makes the theorem very much expected
@JewleZi right, it’s not really surprising, it’s just a tidy little story.
@Joemoeller Ok to be honest it is kind of surprising, when one knows that this does not hold in semi-riemannian geometry, namely there are compact non complete semi-riemannian manifolds. Which is wierd.
@JewleZi that’s awesome. I guess I’d say the theorem is unsurprising if you’re approaching the field naively, as I am.
@Joemoeller maybe the surprising part really is that even tho you can get analogous definitions of everything in the semi-riemannian case, the world is so mich wierder there. And thats also kind of annoying as einstein has been proven right.