luna the doggie 
Huh, so the sign in Portal 2 was correct!
Alexia 
@lunareclipse give it "this statement is "false" "
Catboy Cody 
@lunareclipse Sadly not all signs from Portal 2 work... With some ChatGPT began to explain the logical contradictions to me... Scary... 
But then I realized ChatGPT is just a word-vomiting machine that doesn't think, but just picks the most likely words based on its context and just happened to see the explanation to that contradiction often enough during training.
But then I realized ChatGPT is just a word-vomiting machine that doesn't think, but just picks the most likely words based on its context and just happened to see the explanation to that contradiction often enough during training.
Poslovitch@lunareclipse The paradox I prefer is: "Let R be the set of all sets that are not members of themselves. Is R a member of itself ?" 😁
I think it's Russell's paradox. 🤔
Corbin@Poslovitch @lunareclipse I tested something similar but more obscure; I used Coquand's paradox (really, De Bruijn's paradox) and only about half of the chat.lmsys.org bots can get it right.
For reference, my prompt was, "In mathematics, consider rooted trees: a root and zero or more branches, each branch its own tree. Let a tree be normal iff it is not among its own branches. Is there a tree R such that every normal tree is a branch of R and every branch of R is normal?"
If the bot didn't get it immediately, I sent, "Hint: is R normal?" which is also how I would prompt a human. This worked sometimes.
Leonie 
sophia disorder
@zvava @lunareclipse Personal preference I guess
@koyu @zvava more of a necessity for me really due to astigmatism, this article explains why archive.is/sBeeJ
attached pictures from the article
attached pictures from the article
@lunareclipse @zvava interesting, i will look into that
Freja@lunareclipse it's weird cause that one isn't even a paradox, the answer is just "yes"
(the sign was just misquoting the actual paradox, which is "does the set of all sets which do not contain themselves contain itself")
Birk Marold@lunareclipse mmh works on gpt3.5 and 4🤷
Schaf@lunareclipse very educational game
Tanith the Gay@lunareclipse Huh? That:s not even a paradox tho. The answer's yes, 'f recursive sets're allowed. The paradox arises when looking at the seta all sets which don't contain themselves.