Not one person in the comments has attempted to answer any of the questions either.
Haha good try. Hope your interview goes well

for(var i=0;i<=100;i++){ if((i%2)==1) console.log(i); }

btw % is the modulo operator, x%y returns the remainder of division of x by y

Thank you holy shit I was beginning to think no one has ever seen a fizz buzz before
for (i%1=0; i+2; int) odd++; cout(3)
Will you give me the position if I answer the problems? 😀
Sure! I’ll hire you without even answering the questions. Of course I’m not the op, I dont work in the it field (any more) and none of my open positions involve programming… But you have a job with my company whenever you need one.