At 3 pm UK time this Thursday, December 1, I'm giving my last seminar on representation theory! You can join us on Zoom or in person - details below.

I'll talk about quaternions in physics and Dyson's "three-fold way" - the way the real numbers, complex numbers and quaternions interact.

One cute fact is how an electron is like a quaternion! More precisely: how quaternions show up in the spin-1/2 representation of SU(2) on ℂ².

Let me say a little here...

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https://johncarlosbaez.wordpress.com/2022/09/11/seminar-on-this-weeks-finds/

Seminar on “This Week’s Finds”

Azimuth

We can think of the group SU(2) as the group of unit quaternions: namely, 𝑞 with |𝑞| = 1.

We can think of the space of spinors, ℂ², as the space of quaternions, ℍ.

Then acting on a spinor by an element of SU(2) becomes multiplying a quaternion on the left by a unit quaternion!

But what does it mean to multiply a spinor by 𝑖 in this story? It's multiplying a quaternion on the *right* by the quaternion 𝑖. Note: this commutes with left multiplications by all unit quaternions.

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But there are some subtleties here. For example: multiplying a quaternion on the right by 𝑗 *also* commutes with left multiplication by unit quaternions. But 𝑗 anticommutes with 𝑖:

𝑖𝑗 = −𝑗𝑖

So there must be an 'antilinear' operator on spinors which commutes with the action of SU(2): that is, an operator that anticommutes with multiplication by 𝑖. Moreover this operator squares to -1.

In physics this operator is usually called 'time reversal'. It reverses angular momentum.

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You should have noticed something else, too. Our choice of right multiplication by 𝑖 to make the quaternions into a complex vector space was arbitrary: any unit imaginary quaternion would do! There was also arbitrariness in our choice of 𝑗 to be the time reversal operator.

So there's a whole 2-sphere of different complex structures on the space of spinors, all preserved by the action of SU(2). And after we pick one, there's a circle of different possible time reversal operators!

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The facts in my last paragraph don't rely on describing spinors and SU(2) using quaternions. We could have noticed them in the usual approach using only complex numbers. It just wouldn't be so blindingly obvious.

So, please don't think I'm some nut arguing that spin-1/2 particles are really quaternions. Indeed it seem we need a specific complex structure on the quaternions to recover the usual quantum description of a spin-1/2 particle!

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So far, all I'm saying is that quaternions help clarify some facts about the spin-1/2 particle that would otherwise seem a bit mysterious or weird.

For example, I was always struck by the arbitrariness of the choice of time reversal operator. Physicists usually just pick one! But now I know it corresponds to a choice of a second square root of -1 in the quaternions, one that anticommutes with our first choice: the one we call 𝑖.

At the very least, it's entertaining.

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@johncarlosbaez Since time conjugation squares to \( 1 \), and anticommutes with \( i \), wouldn't it have to be multiplication (on the right) by a split-quaternion? (I've been playing with bi-split-quaternions lately and this might mesh well.)

@Garrett - Hi!

Time reversal only needs to square to some phase, since an overall phase is physically unobservable. For an irreducible unitary group representation, if T is some antilinear operator that squares to a phase, we can prove that phase must be ±1 - see Section 4 here:

http://math.ucr.edu/home/baez/rch.pdf

You don't get to choose which sign you get. For the spin-1/2 rep of SU(2), you get T² = -1. This accords with the usual practice in physics:

https://physics.stackexchange.com/questions/27032/time-reversal-symmetry-and-t2-1

@johncarlosbaez Ah, thanks! These things always go deeper than I think.

@Garrett That's probably also a good position to mention the application for topological superconductors. There the sign of T² is important for classifying systems (the "tenfold way", see [1] or even @johncarlosbaez blog[2]).

Three symmetries are important here, time reversal T, particle hole C and chiral S, which is the combination of the two (the name of the operators differ sometimes).

[1] https://iopscience.iop.org/article/10.1088/1367-2630/12/6/065010
[2] https://math.ucr.edu/home/baez/tenfold.html

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